# Line slope calculator x+8y=16

**Straight line given by points A[0; 2] and B[8; 1]**

## Calculation:

**Slope-intercept form of line:**y = -0.125x+2

**Canonical form of the line equation:**x+8y-16 = 0

**Parametric form of the line equation:**

x = 8t

y = -t+2 ; t ∈ R

**Slope:**m = -0.125

**Slope angle of line: φ =**-7°7'30″ = -0.1244 rad

**X intercept:**x

_{0}= 16

**Y intercept:**y

_{0}= q = 2

**Distance line from the origin:**d

_{0}= 1.9846

**The length of the segment AB: |AB| =**8.0623

**Vector: AB =**(8; -1)

**Normal vector: n =**(1; 8)

**Midpoint of the segment AB: M =**[4; 1.5]

**Perpendicular Bisector equation:**8x-y-30.5 = 0

**Vector OA = (0; 2) ; |OA| = 2**

**Vector OB = (8; 1) ; |OB| = 8.0623**

**Scalar product OA .OB = 2**

**Angle ∠ AOB = 82°52'30″ = 1.4464 rad**